Zulip Chat Archive
Stream: general
Topic: Dagstuhl tasks
Neil Strickland (Oct 17 2018 at 10:00):
Some of you will have seen my post on Mathoverflow (https://mathoverflow.net/q/311159) where I described some tasks that I would like to see formalised for expository purposes, with extensive annotation. I have carried out two of the tasks, and attempted to write useful annotations, as shown on these pages:
http://neilstrickland.staff.shef.ac.uk/dagstuhl/Systems/Lean_mathlib/Tasks/primes/ (infinitely many primes)
http://neilstrickland.staff.shef.ac.uk/dagstuhl/Systems/Lean_mathlib/Tasks/nilpotents/ (the ideal of nilpotents)
These are part of a larger set of pages that are under construction. I would be interested to hear comments.
My annotations include a number of confessions of confusion or ignorance, and I would be happy for
people to enlighten me. There are doubtless other misunderstandings as well that I have not flagged.
Note that these formalisations are designed to optimise comprehensibility for users who know a lot
of mathematics but are new to proof assistants; I am not aiming for efficiency, or for consistency
with standard Lean style in cases where that conflicts with comprehensibility.
Johan Commelin (Oct 17 2018 at 10:48):
@Neil Strickland Cool display mode! In the past there has been discussion here on Zulip on how to generate html docs. This looks really nice. I suppose you could steel a syntax highlighter from somewhere (maybe VScode?) and use that as well.
Johan Commelin (Oct 17 2018 at 10:52):
Also, if you don't care about Lean/mathlib style guides, I would suggest calling the type underlying your comm_ring
just R
instead of α
.
Johan Commelin (Oct 17 2018 at 10:56):
You write
(There is no obvious way to supply an alternative name; Lean rejects
variable [R : comm_ring α]
, for reasons that are not clear to me.)
That is very weird, because Scott is doing this all the time in his category libs. Do you get an actual error?
Maybe you should write include R
afterwards. That will include the instance in all your local contexts. Does that help?
Johan Commelin (Oct 17 2018 at 11:00):
You also write
The resulting heuristics are often effective, but it is also fairly common for the simplifier to apply rules in a way that is unhelpful. In those cases one can instead use the
rewrite
tactic (which can be abbreviated asrw
) to give finer control over what rules are applied in what order.
You might want to mention simp only
and simp [rule]
that can be used to avoid bad simplification steps.
Johan Commelin (Oct 17 2018 at 11:01):
By the way, I must say that I really like these files! You wrote really extensive comments. Thanks a lot!
Neil Strickland (Oct 17 2018 at 11:12):
I hadn't noticed the simp only
thing, thanks for pointing that out. I will have a look and see whether that makes some steps easier.
Johan Commelin (Oct 17 2018 at 11:12):
@Neil Strickland Do you just want us to spam all our feedback into this thread? Or how should we organise this?
Neil Strickland (Oct 17 2018 at 11:16):
That's a good question. I was thinking of putting the whole set of pages and associated code (including Coq and Isabelle stuff) on GitHub, but that will require some organisation, and I haven't really decided on the right structure. So we should probably just use this thread for the time being.
Kevin Buzzard (Oct 17 2018 at 11:16):
Yes I already have some comments about your nilpotent proof
Kevin Buzzard (Oct 17 2018 at 11:17):
(although I am currently on a tram in Sheffield  are you coming to lunch with me?)
Kevin Buzzard (Oct 17 2018 at 11:19):
Lines 520620 or so  these are of no interest to mathematicians and you never need all these intermediate lemmas. You can prove what you want in a couple of lines but it's incomprehensible in some sense. Proving these fiddly things is hard for beginners
Floris van Doorn (Oct 17 2018 at 13:44):
The definition comes from the file mathlib/data/nat/basic.lean (but I do not know a completely automatic way to obtain that information).
You can go to the location where the definition was defined either by ctrl+click, or by clicking on it, and then pressing F12. That will in particular give you the file in which it was defined.
Bryan Ginge Chen (Oct 17 2018 at 14:07):
A few minor typos in the annotations to "primes":

line 10, "The declaration of
min_fac_prime
has the shape:" the declaration that follows is missing<span class="code></span>
around it. 
line 13, "the implicit arguments 𝑝 and 𝑛 are deduced from the context." However, the code uses
@dvd_fact
. 
line 15, "The syntax
(...).mpr
extracts the lefttoright half of this equivalence," should be "righttoleft".
Bryan Ginge Chen (Oct 17 2018 at 14:13):
Have you seen the work in the "tutorials" branch in leanprovercommunity? The files two_add_two.lean
and partitions.lean
tackle tasks 1 and 5 from your MO post, respectively.
Floris van Doorn (Oct 17 2018 at 14:18):
Maybe you should write
include R
afterwards.
This is correct. Lean doesn't automatically inserts variables, unless they are explicitly mentioned in the definition. For example, if I write
variables {α β : Type} def my_id (a : α) : α := a
Then the definition my_id
does not have β
as an argument. If you want to explicitly add a variable/parameter x
to all following definitions, you can write include x
(and stop doing it with omit x
). Because typeclass variables are almost never explicitly mentioned, the (quite arbitrary) convention was added that if you don't give a typeclass variable a name, it is automatically included if all variables in its type are included (so the variable [comm_ring α]
is included when α
is included).
Kevin Buzzard (Oct 17 2018 at 16:31):
(deleted)
Kevin Buzzard (Oct 17 2018 at 16:31):
PS data.nat.binomial
was written by @Chris Hughes  an Imperial maths undergraduate :)
Neil Strickland (Oct 17 2018 at 16:38):
@Bryan Ginge Chen and @Johan Commelin : are you happy for me to steal two_add_two.lean
and partitions.lean
and adapt them to the same framework that I have used for primes and nilpotents?
Johan Commelin (Oct 17 2018 at 16:39):
I'm completely fine with that.
Kevin Buzzard (Oct 17 2018 at 16:40):
@Neil Strickland At line 528 you have p := n + m + 1
and Sn_gt_k : n + 1 > k
and you want m < p  k
. Here's a relatively painless proof which avoids a bunch of intermediate steps.
import data.nat.basic lines 516624 example (n m k : ℕ) (Sn_gt_k : k < n + 1): let p := n + m + 1 in m < p  k := begin apply nat.lt_sub_right_of_add_lt, apply lt_of_lt_of_le (add_lt_add_left Sn_gt_k m), simp, end
Kevin Buzzard (Oct 17 2018 at 16:41):
I think it's hard for learners to prove these things  I have to a certain extent got a nose for which way to go now, but it wouldn't surprise me if Chris, Kenny or Mario could pull off a oneliner. However the real point should be that this is trivial to a mathematician so ideally should be done with a tactic. I tried linarith
(as did you) and I couldn't get it to work. Should it work?
Bryan Ginge Chen (Oct 17 2018 at 16:54):
I'm fine with that too.
Kevin Buzzard (Oct 17 2018 at 17:07):
lemma npz_mul_right (x y : α) (n : ℕ) (xR : next_pow_zero x n) : (next_pow_zero (x * y) n) := begin rw mul_comm, exact npz_mul_left y x n xR end
Kevin Buzzard (Oct 17 2018 at 17:11):
Computer scientists like writing their proofs backwards because then they don't get extra hypotheses cluttering up the context ("things that used to be the goal" are not remembered, whereas old hypotheses are)
Kevin Buzzard (Oct 17 2018 at 17:11):
have Z2 : (n * m + n + m) + 1 = (n + 1) * (m + 1), by simp[add_mul,mul_add,mul_one,one_mul,add_assoc],
I would just put by ring
because why not.
Johan Commelin (Oct 17 2018 at 17:11):
@Neil Strickland In the post by Kevin (above this one) you can see that x
and n
can be determined from xR
. So you can make them implicit, by wrapping them in {}
instead of ()
.
Kevin Buzzard (Oct 17 2018 at 17:25):
The reason it's not dealt with automatically by simp
is I believe that Leo removed add_mul
and mul_add
from the list of simp rules because of some CS reasons.
Kevin Buzzard (Oct 17 2018 at 17:31):
Do you ever use nilpotent_mul_right
and npz_mul_right
?
Mario Carneiro (Oct 17 2018 at 18:44):
because of some CS reasons
aka exponential blowup
Kevin Buzzard (Oct 17 2018 at 18:45):
Like I said
Mario Carneiro (Oct 17 2018 at 18:49):
There are mechanisms that allow Lean to obtain a commutative ring structure automatically from a field structure where necessary, but the resulting commutative ring structure is anonymous. It has been found convenient to include the line
instance : comm_ring ℚ := by apply_instance
in data/rat.lean, which allows us to use the notation rat.comm_ring to refer to the standard commutative ring structure on $\mathbb{Q}$.
Actually this is just to make it faster for lean to discover that Q has a comm_ring instance. Not sure if you want to mention that though.
Mario Carneiro (Oct 17 2018 at 18:52):
There is no obvious way to supply an alternative name; Lean rejects variable [R : comm_ring α], for reasons that are not clear to me.
Johan already mentioned this a bit, but unnamed instance variables are automatically included whenever the variable they reference is included, while a named variable is only included if it is used directly. So if you want to name an instance variable you have to put include R
so it gets included even when it is not referenced.
Mario Carneiro (Oct 17 2018 at 19:01):
We are given a proof (denoted n_le_m) that $n\leq m$. We now apply the theorem nat.succ_le_succ to convert it to a proof that $n+1\leq m+1$. Note that the conclusion of nat.succ_le_succ is actually that succ n ≤ succ m, where succ is the successor function as in Peano arithmetic. One needs to unwind the definitions of $1$ and $+$ to see that n + 1 is the same as succ n. It is not clear to me under what circumstances this unwinding happens automatically, but it seems to work here.
Unfolding of definitions like this happens, quite aggressively, when lean expects something of type T and you give it something of type T', and it tries to figure out why T and T' are the same (definitionally equal). Most tactics, on the other hand, are sensitive to the exact way you write an expression, so for example rw
would not work on a term of type next_pow_zero
even though it is an equality after some unfolding. You can also obtain the result of line 18 in a more automatic way by using unfold next_pow_zero at xR
.
Mario Carneiro (Oct 17 2018 at 19:03):
L19:
Note that we have given the name Sn_le_Sm to our conclusion. The Lean documentation says that one can use the keyword have with no label, and use the keyword this to refer to the most recently proved statement. However, this does not seem to work here. I think that this is because we are in tactic mode, and anonymous have only works outside that mode. But the full story is not clear to me.
Anonymous have should work here. You can put have : n + 1 ≤ m + 1 := (succ_le_succ n_le_m),
on this line and use this
instead of Sn_le_Sm
in L21, and it should work. If not, let me know what error you get
Mario Carneiro (Oct 17 2018 at 20:24):
Unless you specifically want to focus on nat subtraction and how annoying it is to work with for pedagogical reasons, I would suggest using le.dest
to avoid it altogether. This also gives you a chance to use rcases
which I think is worth calling out.
lemma npz_shift (x : α) (n m : ℕ) (xR : next_pow_zero x n) (n_le_m : n ≤ m) : next_pow_zero x m := begin unfold next_pow_zero at xR, have : n + 1 ≤ m + 1 := succ_le_succ n_le_m, have : ∃ k, (n + 1) + k = (m + 1) := le.dest this, rcases this with ⟨k, SnkSm⟩, show x^(m + 1) = 0, rw [← SnkSm, _root_.pow_add, xR, zero_mul], end
Mario Carneiro (Oct 17 2018 at 21:08):
Here's a proof of npz_add
with a few comments of my own. I tried not to overoptimize it and keep it pedagogical:
 The first few parameters are implicit because they follow from the types of xR and yR lemma npz_add {x y : α} {n m : ℕ} (xR : next_pow_zero x n) (yR : next_pow_zero y m) : next_pow_zero (x + y) (n + m) := begin unfold next_pow_zero at xR yR ⊢,  we want to unfold this definition everywhere so it doesn't get in the way let p := n + m + 1, suffices : ∀ (k : ℕ) (h : k ∈ (range (succ p))), x ^ k * y ^ (p  k) * ↑(choose p k) = 0,  Let us use suffices so that we know why we are proving this { exact calc (x + y)^p = (range (succ p)).sum (λ k, x ^ k * y ^ (p  k) * ↑(choose p k)) : add_pow x y p  use binomial theorem ... = (range (succ p)).sum (λ k, (0 : α)) : finset.sum_congr rfl this  use the assumption ... = 0 : sum_const_zero },  note for Neil: use {} instead of begin end to make it clearer that syntax  in tactic mode is different than term mode.  Similarly 'by' is unnecessary in tactic mode intros k h, have k_lt_Sp : k < p + 1 := mem_range.mp h, have k_le_p : k ≤ p := le_of_lt_succ k_lt_Sp,  note the name of the theorem is derivable from the statement (very important!) rcases le_or_gt (n + 1) k with Sn_le_k  Sn_gt_k, { rcases le.dest Sn_le_k with ⟨j, Z0⟩,  note Z0 : (n + 1) + j = k have Z1 : x ^ (n + 1) = 0 := xR,  Note at this point that theorem Z2 is actually a special case  of npz_shift, so maybe we should go back and generalize it? Exercise for the reader have Z2 : x ^ k = 0, { rw [← Z0,  x ^ (n + 1 + j) = 0 _root_.pow_add,  x ^ (n + 1) * x ^ j = 0 Z1,  0 * x ^ j = 0 zero_mul] }, simp [Z2] }, { have k_le_n : k ≤ n := lt_succ_iff.mp Sn_gt_k, rcases le.dest k_le_n with ⟨j, Z0⟩,  Z0 : k + j = n have Z4 : p  k = (m + 1) + j, { apply nat.sub_eq_of_eq_add,  get rid of the subtraction because nat subtraction sucks simp [p, Z0.symm] },  After unfolding p and using Z0.symm : n = k + j, the goal is  (k + j) + m + 1 = k + (m + 1 + j) which simp can handle  (just associativity and commutativity of addition) have Z6 : y ^ (p  k) = 0, { rw [Z4, _root_.pow_add, yR, zero_mul] }, simp [Z6] } end
Alex J. Best (Oct 17 2018 at 23:59):
Hi @Neil Strickland the viewer is really cool! The tex doesn't load for me though but if I add MathJax.Hub.Queue(["Typeset",MathJax.Hub]);
to viewer.js line 102 above this.show_comment(0);
it does.
Neil Strickland (Oct 18 2018 at 02:08):
Thanks to everyone for your feedback. I am working on incorporating it and also improving my infrastructure in various ways; I will report back in a day or two.
Scott Morrison (Oct 18 2018 at 02:47):
I'd love to see your infrastructure turn into leandoc
. :)
Scott Morrison (Oct 18 2018 at 02:49):
Can I suggest that you don't embed html in the source code, but use markdown instead? I don't think we're ever going to want to include html in source files, but markdown ($ ... $ for math is of course fine) is great.
David Michael Roberts (Oct 18 2018 at 07:56):
@Neil Strickland I am using the latest version of Chrome (69.0.3497.100 (Official Build) (64bit)) on OS X 10.10.5 and I see this: Code from "There are infinitely many primes"
Bryan Ginge Chen (Oct 18 2018 at 16:15):
Line 145 in nilpotents
:
def is_reduced (α : Type*) [comm_ring α] : Prop :=
I am not completely clear about the mechanism for handling implicit and explicit arguments here. At the beginning of this file we opened a section and had the declaration
variable {α : Type u}
. [...] It seems that the declaration here overrides the default behaviour and converts𝛼
to an explicit argument. The ring structure on𝛼
remains an implicit argument handled by typeclass inference, however.
It's my understanding that when you explicitly include in a def
some variable 𝛼
with the same name as one in an earlier variable
declaration, lean locally creates a new variable which is unrelated to the other 𝛼
; in particular, previous typeclass assignments won't apply to the new 𝛼
, and that's why you had to put in [comm_ring 𝛼]
here again.
To convert an existing variable from implicit to explicit, write variable (𝛼)
on the line before this definition. Then when you want to let 𝛼
be implicit again (presumably after 158), you can write variable {𝛼}
.
Bryan Ginge Chen (Oct 18 2018 at 16:34):
Typo in the comments to line 153154 in nilpotents
: there's a missing space in "init/data/setoid.lean
in".
Including the types explicitly in lines 153 and 159 would make things more readable to me: def reduced_quotient (α : Type*) [comm_ring α] : Type* :=
and instance reduced_quotient_mk_is_ring_hom : is_ring_hom quotient_ring.mk :=
.
I'm not sure what "further problems related to implicit arguments" occurred that required you to write lines 168178 but if you say more perhaps we can figure it out.
Last updated: May 15 2021 at 22:14 UTC