Zulip Chat Archive
Stream: general
Topic: What topological spaces do we have?
Kenny Lau (Mar 27 2018 at 22:33):
I'm aware that this place does not value examples, just abstract theorems, but do we have R^n? C^n? S^n? D^n?
Kenny Lau (Mar 27 2018 at 22:33):
by "this place" I mean Mario
Mario Carneiro (Mar 27 2018 at 23:41):
I like examples when they are abstract constructions :)
Mario Carneiro (Mar 27 2018 at 23:42):
In this case you're talking about making a topological space out of K^n where K is a topological field or vector space
Kenny Lau (Mar 27 2018 at 23:52):
that's only the first two cases :)
Mario Carneiro (Mar 27 2018 at 23:54):
For S^n and D^n, I would just define them as the appropriate subspaces. There are loads of more abstract definitions of S^n of course, but I would suggest sticking to actual spheres for the definition
Kenny Lau (Mar 27 2018 at 23:55):
agreed, but do you have norm?
Mario Carneiro (Mar 27 2018 at 23:55):
Patrick had a working definition
Kenny Lau (Mar 27 2018 at 23:55):
in R^n?
Mario Carneiro (Mar 27 2018 at 23:56):
Hm, it occurs to me that "the unit sphere" is well defined in any normed vector space
Kenny Lau (Mar 27 2018 at 23:57):
for god's sake
Mario Carneiro (Mar 27 2018 at 23:57):
Patrick's definition gives a norm on any normed space
Mario Carneiro (Mar 27 2018 at 23:57):
of course R^n will be a normed space
Mario Carneiro (Mar 27 2018 at 23:58):
but there is some concern about whether to use the 2-norm vs some other p-norm
Mario Carneiro (Mar 27 2018 at 23:59):
If you just need something quick and dirty for some application, go ahead and define it however you like
Kenny Lau (Mar 28 2018 at 00:00):
I don’t need it now
Mario Carneiro (Mar 28 2018 at 00:00):
The simplest abstract definition if you only need the topological structure is by iterating the suspension operation on bool
Kenny Lau (Mar 28 2018 at 00:01):
good luck proving that S^n \ {pt} ~ R^n
Kenny Lau (Mar 28 2018 at 00:02):
good luck finding a single point inside
Mario Carneiro (Mar 28 2018 at 00:03):
I guess it's not obvious that S^n is homogeneous as the suspension, but it's easy to show S^n \ {north pole} ~ R^n
Kenny Lau (Mar 28 2018 at 00:04):
hmm
Kenny Lau (Mar 28 2018 at 00:05):
and R^n \ {0} def retracts to S^(n-1)?
Mario Carneiro (Mar 28 2018 at 00:06):
That's dead easy with the suspension, since R^n\{0} maps to S^(n-1) x (0,1)
Kenny Lau (Mar 28 2018 at 00:07):
tu ganhas
Mario Carneiro (Mar 28 2018 at 00:08):
I agree that homogeneity is easier with the geometric representation, since then you can use orthogonal transformations
Kenny Lau (Mar 28 2018 at 00:08):
next time someone asks me what S^n is, I’m gonna say “repeated suspension of bool” :stuck_out_tongue:
Kenny Lau (Mar 28 2018 at 00:08):
they be like “entao o que e bool?”
Mario Carneiro (Mar 28 2018 at 00:08):
I think that's the definition the HoTT people use, more or less
Mario Carneiro (Mar 28 2018 at 00:09):
Also, if you do repeated suspension on unit
you get D^n
Mario Carneiro (Mar 28 2018 at 00:10):
or just take [0,1]^n
Mario Carneiro (Mar 28 2018 at 00:11):
But for a mathlib definition, I would imagine it will be used in many contexts, not just topological, i.e. you might care about manifold structure in which case "corners" are not appreciated
Patrick Massot (Mar 28 2018 at 07:53):
I almost have as a topological space. I only need to find one day without a million urgent things to do. I have normed spaces and Pi instances for many things. But indeed the norm we'll have on will have box balls, which is not good if you want to get a smooth .
Kenny Lau (Mar 29 2018 at 06:49):
https://math.stackexchange.com/a/2712786/328173
Kenny Lau (Mar 29 2018 at 06:49):
@Mario Carneiro this is part of the reason I asked that question
Kenny Lau (Mar 29 2018 at 06:49):
if we have enough lemmas we might be able to formalize that
Last updated: Dec 20 2023 at 11:08 UTC