Zulip Chat Archive
Stream: general
Topic: filter map on the set level
Bernd Losert (Jan 06 2022 at 23:09):
Say I have m : set α → set α and f : filter α. How do I "map" m on f?
Floris van Doorn (Jan 06 2022 at 23:10):
You need some conditions on m
to know that any such result is again a filter.
Bernd Losert (Jan 06 2022 at 23:11):
I'm not too worried about that since I can use filter.generate
to get a filter back.
Floris van Doorn (Jan 06 2022 at 23:11):
maybe docs#filter.map and docs#filter.comap are relevant.
Bernd Losert (Jan 06 2022 at 23:11):
Unfortunately, map
and comap
are not going to work.
Floris van Doorn (Jan 06 2022 at 23:13):
It sounds like you want something like
def my_map {α β} (m : set α → set β) (f : filter α) : filter β :=
filter.generate (m '' f.sets)
I don't know if that is a sensible construction though.
Bernd Losert (Jan 06 2022 at 23:14):
Remind me what ''
does.
Floris van Doorn (Jan 06 2022 at 23:15):
it's the image of a set under a function, docs#set.image
Bernd Losert (Jan 06 2022 at 23:15):
Ah, that's right. I had forgotten about it. Thanks.
Floris van Doorn (Jan 06 2022 at 23:21):
I think the bigger question is: what do you want this map of m on f to do, or what properties do you want it do have?
Adam Topaz (Jan 06 2022 at 23:29):
Isn't there some Galois connection between sets and filters somewhere?
Floris van Doorn (Jan 06 2022 at 23:39):
sure: docs#filter.gi_generate
Bernd Losert (Jan 06 2022 at 23:41):
Floris van Doorn said:
I think the bigger question is: what do you want this map of m on f to do, or what properties do you want it do have?
I have defined the closure cl
of a set as an operator of type set X -> set X. I want to build the "closure" of a filter by applying cl
to each of the sets in the filter.
Last updated: Dec 20 2023 at 11:08 UTC