Zulip Chat Archive
Stream: maths
Topic: Increasing convergent subsequence
Koundinya Vajjha (Jul 19 2019 at 18:38):
Is there a result in mathlib which constructs a monotone convergent subsequence out of a convergent sequence?
Kevin Buzzard (Jul 19 2019 at 18:45):
Of reals? I think Bolzano Weierstrass is in there somewhere and it's relatively straightforward from there, the statement about a subsequence tending to the same thing as the sequence will just be some filter magic
Koundinya Vajjha (Jul 19 2019 at 18:46):
Yes I'm working with nnreal
.
Kevin Buzzard (Jul 19 2019 at 18:46):
Wait I don't mean Bolzano Weierstrass
Kevin Buzzard (Jul 19 2019 at 18:47):
I mean the assertion that a sequence has a monotonic subsequence
Kevin Buzzard (Jul 19 2019 at 18:47):
This is just some basic fact about total orders
Kevin Buzzard (Jul 19 2019 at 18:47):
You look at the peaks of the sequence
Koundinya Vajjha (Jul 19 2019 at 18:47):
Can you point me to the result? I'm new to filters/sequences and I have no idea where to look
Mario Carneiro (Jul 19 2019 at 18:48):
it's not proven in mathlib AFAIK
Kevin Buzzard (Jul 19 2019 at 18:49):
I don't know my way around that part of the library
Mario Carneiro (Jul 19 2019 at 18:51):
What do you need it for? It looks like a pretty gimmicky result to me
Koundinya Vajjha (Jul 19 2019 at 18:52):
Here is my set-up. I have a set K
and have proven that there is a sequence x : nat -> K
such that x n
tends to Sup K
. I need to prove that the interval Icc (Sup K) t
is the intersection of the intervals Icc (x n) t
where t
is a fixed nnreal.
Mario Carneiro (Jul 19 2019 at 18:52):
wait that's a lot easier
Mario Carneiro (Jul 19 2019 at 18:53):
because it's not just monotone it's monotone increasing
Koundinya Vajjha (Jul 19 2019 at 18:53):
Yes
Mario Carneiro (Jul 19 2019 at 18:54):
Actually you don't even need that, this is just the definition of Sup
Koundinya Vajjha (Jul 19 2019 at 18:54):
Can you elaborate?
Koundinya Vajjha (Jul 19 2019 at 18:55):
I thought I needed an increasing subsequence
Mario Carneiro (Jul 19 2019 at 18:55):
Sup K <= a iff for all k in K, k <= a
Koundinya Vajjha (Jul 19 2019 at 18:56):
Oh! I see!
Mario Carneiro (Jul 19 2019 at 18:56):
For any k in K, either k = Sup K or there exists k <= x n < Sup K
Last updated: Dec 20 2023 at 11:08 UTC