Zulip Chat Archive
Stream: Is there code for X?
Topic: Continuous of neighborhoods
Aaron Liu (Jun 27 2025 at 12:07):
I want to prove a function is continuous from its action on neighborhoods, so the converse to docs#Continuous.tendsto. I couldn't find this theorem anywhere.
import Mathlib
example {X Y : Type*} [TopologicalSpace X] [TopologicalSpace Y] {f : X → Y}
(hf : ∀ x : X, Filter.Tendsto f (nhds x) (nhds (f x))) : Continuous f := by
sorry
Junyan Xu (Jun 27 2025 at 12:11):
hf x is it's the definition of ContinuousAt
Aaron Liu (Jun 27 2025 at 12:11):
Is that meant to be unfolded?
Junyan Xu (Jun 27 2025 at 12:12):
(so you can use continuous_iff_continuousAt)
(I think the answer is you should stick to the ContinuousAt API rather than unfolding it)
Aaron Liu (Jun 27 2025 at 12:14):
If I don't want to unfold it then how do I get ContinuousAt x ↔ Filter.Tendsto f (nhds x) (nhds (f x))?
Kenny Lau (Jun 27 2025 at 12:24):
@Aaron Liu ContinuousAt.tendsto
Kenny Lau (Jun 27 2025 at 12:24):
and continuousAt_of_tendsto_nhds for the other direction
Aaron Liu (Jun 27 2025 at 12:24):
No I want the other direction
Aaron Liu (Jun 27 2025 at 12:25):
Kenny Lau said:
and
continuousAt_of_tendsto_nhdsfor the other direction
- This needs
T1Space(which is not a problem for me but I thought I'd mention it anyways) - It's very annoying to use this with
applysince I get?yin my goal
Aaron Liu (Jun 27 2025 at 12:31):
For context, I want to prove a function partially defined on a quotient (so from a subtype of a quotient) is continuous, so it's much easier to work with neighborhoods since then I can use lemmas like docs#nhds_subtype.
Anatole Dedecker (Jun 27 2025 at 15:08):
With the current API unfolding is the best solution.
Last updated: Dec 20 2025 at 21:32 UTC