Iterate maps and comaps of submodules #
Some preliminary work for establishing the strong rank condition for noetherian rings.
Given two linear maps f i : N →ₗ[R] M
and a submodule K : Submodule R N
, we can define
LinearMap.iterateMapComap f i n K : Submodule R N
to be f⁻¹(i(⋯(f⁻¹(i(K)))))
(n
times).
If f(K) ≤ i(K)
, then this sequence is non-decreasing (LinearMap.iterateMapComap_le_succ
).
On the other hand, if f
is surjective, i
is injective, and there exists some m
such that
LinearMap.iterateMapComap f i m K = LinearMap.iterateMapComap f i (m + 1) K
,
then for any n
,
LinearMap.iterateMapComap f i n K = LinearMap.iterateMapComap f i (n + 1) K
.
In particular, by taking n = 0
, the kernel of f
is contained in K
(LinearMap.ker_le_of_iterateMapComap_eq_succ
),
which is a consequence of LinearMap.ker_le_comap
.
As a special case, if one can take K
to be zero,
then f
is injective. This is the key result for establishing the strong rank condition
for noetherian rings.
The construction here is adapted from the proof in Djoković's paper Epimorphisms of modules which must be isomorphisms [Djo73].
The LinearMap.iterateMapComap f i n K : Submodule R N
is
f⁻¹(i(⋯(f⁻¹(i(K)))))
(n
times).
Equations
- f.iterateMapComap i n = (fun (K : Submodule R N) => Submodule.comap f (Submodule.map i K))^[n]
Instances For
If f(K) ≤ i(K)
, then LinearMap.iterateMapComap
is not decreasing.
If f
is surjective, i
is injective, and there exists some m
such that
LinearMap.iterateMapComap f i m K = LinearMap.iterateMapComap f i (m + 1) K
,
then for any n
,
LinearMap.iterateMapComap f i n K = LinearMap.iterateMapComap f i (n + 1) K
.
In particular, by taking n = 0
, the kernel of f
is contained in K
(LinearMap.ker_le_of_iterateMapComap_eq_succ
),
which is a consequence of LinearMap.ker_le_comap
.
If f
is surjective, i
is injective, and there exists some m
such that
LinearMap.iterateMapComap f i m K = LinearMap.iterateMapComap f i (m + 1) K
,
then the kernel of f
is contained in K
.
This is a corollary of LinearMap.iterateMapComap_eq_succ
and LinearMap.ker_le_comap
.
As a special case, if one can take K
to be zero,
then f
is injective. This is the key result for establishing the strong rank condition
for noetherian rings.