Displacement is at most the integral of the speed #
In this file we prove several version of the following fact:
the displacement (dist (f a) (f b)) is at most the integral of ‖deriv f‖ over [a, b].
Displacement is at most the integral of an upper estimate on the speed.
Let f : ℝ → E be a function which is continuous on a closed interval [a, b]
and is differentiable on the open interval (a, b).
If B t is an integrable upper estimate on ‖f' t‖, a < t < b,
then ‖f b - f a‖ ≤ ∫ t in a..b, B t.
Let f : ℝ → E be a function which is continuous on [a, b] and is differentiable on (a, b).
Suppose that ‖f' t‖ ≤ C for a.e. t ∈ (a, b).
Then the distance between f a and f b
is at most C times the measure of x ∈ (a, b) such that f' x ≠ 0.
This lemma is useful, if f is known to have zero derivative at most points of [a, b].
Consider a function f : E → F continuous on a segment [a, b]
and line differentiable in the direction b - a at all points of the open segment (a, b).
If ‖∂_{b - a} f‖ ≤ C at a.e. all points of the open segment,
then ‖f b - f a‖ ≤ C * volume s, where s is the set of points t ∈ Ioo 0 1
such that f has nonzero line derivative in the direction b - a at lineMap a b t.
Let f : E → F be a function differentiable on a set s and continuous on its closure.
Let a, b be two points such that the open segment connecting a to b is a subset of s.
If ‖Df‖ ≤ C everywhere on s then ‖f b - f a‖ ≤ C * volume u,
where u is the set of points t ∈ Ioo 0 1
such that f has nonzero derivative at lineMap a b t.
Let f : E → F be a function differentiable in a neighborhood of a.
If $Df(x) = O(‖x - a‖ ^ r)$ as x → a, where r ≥ 0,
then $f(x) - f(a) = O(‖x - a‖ ^ {r + 1})$ as x → a.
Let f : E → F be a function differentiable in a neighborhood of a.
If $Df(x) = O(‖x - a‖ ^ r)$ as x → a, where r ≥ 0, and f a = 0,
then $f(x) = O(‖x - a‖ ^ {r + 1})$ as x → a.