Bases of submodules #
If the submodule P
has a basis, x ∈ P
iff it is a linear combination of basis vectors.
If the submodule P
has a finite basis,
x ∈ P
iff it is a linear combination of basis vectors.
If N
is a submodule with finite rank, do induction on adjoining a linear independent
element to a submodule.
Equations
- One or more equations did not get rendered due to their size.
Instances For
An element of a non-unital-non-associative algebra is in the center exactly when it commutes with the basis elements.
Let b
be an S
-basis of M
. Let R
be a CommRing such that Algebra R S
has no zero smul
divisors, then the submodule of M
spanned by b
over R
admits b
as an R
-basis.
Equations
- Basis.restrictScalars R b = Basis.span ⋯
Instances For
Let b
be an S
-basis of M
. Then m : M
lies in the R
-module spanned by b
iff all the
coordinates of m
on the basis b
are in R
(see Basis.mem_span
for the case R = S
).
Let A
be an subgroup of an additive commutative group M
that is also an R
-module.
Construct a basis of A
as a ℤ
-basis from a R
-basis of E
that generates A
.
Equations
- Basis.addSubgroupOfClosure A b h = (Basis.restrictScalars ℤ b).map (LinearEquiv.ofEq (Submodule.span ℤ (Set.range ⇑b)) (AddSubgroup.toIntSubmodule A) ⋯)