Ramification index and inertia degree #
Given P : Ideal S lying over p : Ideal R for the ring extension f : R →+* S
(assuming P and p are prime or maximal where needed),
the inertia degree Ideal.inertiaDeg p P is the degree of the field extension
(S / P) : (R / p).
Implementation notes #
Often the above theory is set up in the case where:
Ris the ring of integers of a number fieldK,Lis a finite separable extension ofK,Sis the integral closure ofRinL,pandPare maximal ideals,Pis an ideal lying overpWe will try to relax the above hypotheses as much as possible.
Notation #
In this file, f stands for the inertia degree of P over p, leaving p and P implicit.
The inertia degree of P : Ideal S lying over p : Ideal R is the degree of the
extension (S / P) : (R / p).
We do not assume P lies over p in the definition; we return 0 instead.
See inertiaDeg_algebraMap for the common case where f = algebraMap R S
and there is an algebra structure R / p → S / P.
Equations
- p.inertiaDeg P = if hPp : Ideal.comap (algebraMap R S) P = p then Module.finrank (R ⧸ p) (S ⧸ P) else 0
Instances For
The absolute norm of an ideal P above a rational prime p is
|p| ^ ((span {p}).inertiaDeg P).
See absNorm_eq_pow_inertiaDeg' for a version with p of type ℕ.
The absolute norm of an ideal P above a rational (positive) prime p is
p ^ ((span {p}).inertiaDeg P).
See absNorm_eq_pow_inertiaDeg for a version with p of type ℤ.
Let T / S / R be a tower of algebras, p, P, I be ideals in R, S, T, respectively,
and p and P are maximal. If p = P ∩ S and P = I ∩ S,
then f (I | p) = f (P | p) * f (I | P).