Urysohn's lemma #
In this file we prove Urysohn's lemma exists_continuous_zero_one_of_isClosed
: for any two disjoint
closed sets s
and t
in a normal topological space X
there exists a continuous function
f : X → ℝ
such that
f
equals zero ons
;f
equals one ont
;0 ≤ f x ≤ 1
for allx
.
We also give versions in a regular locally compact space where one assumes that s
is compact
and t
is closed, in exists_continuous_zero_one_of_isCompact
and exists_continuous_one_zero_of_isCompact
(the latter providing additionally a function with
compact support).
We write a generic proof so that it applies both to normal spaces and to regular locally compact spaces.
Implementation notes #
Most paper sources prove Urysohn's lemma using a family of open sets indexed by dyadic rational
numbers on [0, 1]
. There are many technical difficulties with formalizing this proof (e.g., one
needs to formalize the "dyadic induction", then prove that the resulting family of open sets is
monotone). So, we formalize a slightly different proof.
Let Urysohns.CU
be the type of pairs (C, U)
of a closed set C
and an open set U
such that
C ⊆ U
. Since X
is a normal topological space, for each c : CU
there exists an open set u
such that c.C ⊆ u ∧ closure u ⊆ c.U
. We define c.left
and c.right
to be (c.C, u)
and
(closure u, c.U)
, respectively. Then we define a family of functions
Urysohns.CU.approx (c : Urysohns.CU) (n : ℕ) : X → ℝ
by recursion on n
:
c.approx 0
is the indicator ofc.Uᶜ
;c.approx (n + 1) x = (c.left.approx n x + c.right.approx n x) / 2
.
For each x
this is a monotone family of functions that are equal to zero on c.C
and are equal to
one outside of c.U
. We also have c.approx n x ∈ [0, 1]
for all c
, n
, and x
.
Let Urysohns.CU.lim c
be the supremum (or equivalently, the limit) of c.approx n
. Then
properties of Urysohns.CU.approx
immediately imply that
c.lim x ∈ [0, 1]
for allx
;c.lim
equals zero onc.C
and equals one outside ofc.U
;c.lim x = (c.left.lim x + c.right.lim x) / 2
.
In order to prove that c.lim
is continuous at x
, we prove by induction on n : ℕ
that for y
in a small neighborhood of x
we have |c.lim y - c.lim x| ≤ (3 / 4) ^ n
. Induction base follows
from c.lim x ∈ [0, 1]
, c.lim y ∈ [0, 1]
. For the induction step, consider two cases:
x ∈ c.left.U
; then fory
in a small neighborhood ofx
we havey ∈ c.left.U ⊆ c.right.C
(hencec.right.lim x = c.right.lim y = 0
) and|c.left.lim y - c.left.lim x| ≤ (3 / 4) ^ n
. Then|c.lim y - c.lim x| = |c.left.lim y - c.left.lim x| / 2 ≤ (3 / 4) ^ n / 2 < (3 / 4) ^ (n + 1)
.- otherwise,
x ∉ c.left.right.C
; then fory
in a small neighborhood ofx
we havey ∉ c.left.right.C ⊇ c.left.left.U
(hencec.left.left.lim x = c.left.left.lim y = 1
),|c.left.right.lim y - c.left.right.lim x| ≤ (3 / 4) ^ n
, and|c.right.lim y - c.right.lim x| ≤ (3 / 4) ^ n
. Combining these inequalities, the triangle inequality, and the recurrence formula forc.lim
, we get|c.lim x - c.lim y| ≤ (3 / 4) ^ (n + 1)
.
The actual formalization uses midpoint ℝ x y
instead of (x + y) / 2
because we have more API
lemmas about midpoint
.
Tags #
Urysohn's lemma, normal topological space, locally compact topological space
An auxiliary type for the proof of Urysohn's lemma: a pair of a closed set C
and its
open neighborhood U
, together with the assumption that C
satisfies the property P C
. The
latter assumption will make it possible to prove simultaneously both versions of Urysohn's lemma,
in normal spaces (with P
always true) and in locally compact spaces (with P = IsCompact
).
We put also in the structure the assumption that, for any such pair, one may find an intermediate
pair in between satisfying P
, to avoid carrying it around in the argument.
- C : Set X
The inner set in the inductive construction towards Urysohn's lemma
- U : Set X
The outer set in the inductive construction towards Urysohn's lemma
- P_C : P self.C
- closed_C : IsClosed self.C
- open_U : IsOpen self.U
- subset : self.C ⊆ self.U
Instances For
By assumption, for each c : CU P
there exists an open set u
such that c.C ⊆ u
and closure u ⊆ c.U
. c.left
is the pair (c.C, u)
.
Equations
- c.left = { C := c.C, U := ⋯.choose, P_C := ⋯, closed_C := ⋯, open_U := ⋯, subset := ⋯, hP := ⋯ }
Instances For
By assumption, for each c : CU P
there exists an open set u
such that c.C ⊆ u
and closure u ⊆ c.U
. c.right
is the pair (closure u, c.U)
.
Equations
Instances For
n
-th approximation to a continuous function f : X → ℝ
such that f = 0
on c.C
and f = 1
outside of c.U
.
Equations
- Urysohns.CU.approx 0 x✝¹ x✝ = x✝¹.Uᶜ.indicator 1 x✝
- Urysohns.CU.approx n.succ x✝¹ x✝ = midpoint ℝ (Urysohns.CU.approx n x✝¹.left x✝) (Urysohns.CU.approx n x✝¹.right x✝)
Instances For
A continuous function f : X → ℝ
such that
Equations
- c.lim x = ⨆ (n : ℕ), Urysohns.CU.approx n c x
Instances For
Continuity of Urysohns.CU.lim
. See module docstring for a sketch of the proofs.
Urysohn's lemma: if s
and t
are two disjoint closed sets in a normal topological space X
,
then there exists a continuous function f : X → ℝ
such that
f
equals zero ons
;f
equals one ont
;0 ≤ f x ≤ 1
for allx
.
Urysohn's lemma: if s
and t
are two disjoint sets in a regular locally compact topological
space X
, with s
compact and t
closed, then there exists a continuous
function f : X → ℝ
such that
f
equals zero ons
;f
equals one ont
;0 ≤ f x ≤ 1
for allx
.
Urysohn's lemma: if s
and t
are two disjoint sets in a regular locally compact topological
space X
, with s
compact and t
closed, then there exists a continuous
function f : X → ℝ
such that
f
equals zero ont
;f
equals one ons
;0 ≤ f x ≤ 1
for allx
.
Urysohn's lemma: if s
and t
are two disjoint sets in a regular locally compact topological
space X
, with s
compact and t
closed, then there exists a continuous compactly supported
function f : X → ℝ
such that
f
equals one ons
;f
equals zero ont
;0 ≤ f x ≤ 1
for allx
.
Urysohn's lemma: if s
and t
are two disjoint sets in a regular locally compact topological
space X
, with s
compact and t
closed, then there exists a continuous compactly supported
function f : X → ℝ
such that
f
equals one ons
;f
equals zero ont
;0 ≤ f x ≤ 1
for allx
.
Moreover, if s
is Gδ, one can ensure that f ⁻¹ {1}
is exactly s
.
A variation of Urysohn's lemma. In a T2Space X
, for a closed set t
and a relatively
compact open set s
such that t ⊆ s
, there is a continuous function f
supported in s
,
f x = 1
on t
and 0 ≤ f x ≤ 1
.