# Integral closure as a characteristic predicate #
We prove basic properties of IsIntegralClosure.
The inverse of an integral element in a subalgebra of a division ring over a field also lies in that subalgebra.
An integral subalgebra of a division ring over a field is closed under inverses.
The inverse of an integral element in a division ring over a field is also integral.
The Kurosh problem asks to show that
this is still true when A is not necessarily commutative and R is a field, but it has
been solved in the negative. See https://arxiv.org/pdf/1706.02383.pdf for criteria for a
finitely generated algebraic (= integral) algebra over a field to be finite dimensional.
This could be an instance, but we tend to go from Module.Finite to IsIntegral/IsAlgebraic,
and making it an instance will cause the search to be complicated a lot.
Alias of RingHom.IsIntegral.to_finite.
An AlgHom between two rings restrict to an AlgHom between the integral closures inside
them.
Equations
- f.mapIntegralClosure = (AlgHom.restrictDomain (↥(integralClosure R A)) f).codRestrict (integralClosure R S) ⋯
Instances For
An AlgEquiv between two rings restrict to an AlgEquiv between the integral closures inside
them.
Equations
- f.mapIntegralClosure = AlgEquiv.ofAlgHom (↑f).mapIntegralClosure (↑f.symm).mapIntegralClosure ⋯ ⋯
Instances For
Generalization of IsIntegral.of_mem_closure bootstrapped up from that lemma
Given a p : R[X] and a x : S such that p.eval₂ f x = 0,
f p.leadingCoeff * x is integral.
Given a p : R[X] and a root x : S,
then p.leadingCoeff • x : S is integral over R.
If x : B is integral over R, then it is an element of the integral closure of R in B.
Equations
- IsIntegralClosure.mk' A x hx = Classical.choose ⋯
Instances For
The integral closure of a field in a commutative domain is always a field.
If B / S / R is a tower of ring extensions where S is integral over R,
then S maps (uniquely) into an integral closure B / A / R.
Equations
- IsIntegralClosure.lift R A B = { toFun := fun (x : S) => IsIntegralClosure.mk' A ((algebraMap S B) x) ⋯, map_one' := ⋯, map_mul' := ⋯, map_zero' := ⋯, map_add' := ⋯, commutes' := ⋯ }
Instances For
Integral closures are all isomorphic to each other.
Equations
- IsIntegralClosure.equiv R A B A' = AlgEquiv.ofAlgHom (IsIntegralClosure.lift R A' B) (IsIntegralClosure.lift R A B) ⋯ ⋯
Instances For
If A is an R-algebra all of whose elements are integral over R, and x is an element of an A-algebra that is integral over A, then x is integral over R.
If A is an R-algebra all of whose elements are integral over R, and B is an A-algebra all of whose elements are integral over A, then all elements of B are integral over R.
If R → A → B is an algebra tower, C is the integral closure of R in B
and A is integral over R, then C is the integral closure of A in B.
If R → A → B is an algebra tower with A → B injective,
then if the entire tower is an integral extension so is R → A
Let T / S / R be a tower of algebras, T is non-trivial and is a torsion free S-module,
then if T is an integral R-algebra, then S is an integral R-algebra.
Let T / S / R be a tower of algebras, T is an integral R-algebra, then it is integral
as an S-algebra.
If the integral extension R → S is injective, and S is a field, then R is also a field.