Ramification index and inertia degree #
This file proves that the sum of ramification times inertia equals the degree of the extension.
Typically this is only stated for extensions of Dedekind domains, but we prove it for any finite flat extension of an integral domain.
Main results #
Ideal.sum_ramification_inertia_eq_finrank: LetRbe an integral domain, letSbe a finite flatR-algebra, and letpbe a prime ideal ofR. Then the sum over all prime idealsqofSlying overpof the ramification index ofqtimes the inertia degree ofqequals the rank ofSas anR-module.Ideal.sum_ramification_inertia_eq_card: LetS/Rbe a finite flat extension of domains, and letpbe prime ideal ofR. Assume thatRis the invariant subring of a finite groupGacting onS. Then the sum over all prime idealsqofSlying overpof the ramification index ofqtimes the inertia degree ofqequals the cardinality ofG.
Let R be an integral domain, let S be a finite flat R-algebra, and let p be a prime
ideal of R. Then the sum over all prime ideals q of S lying over p of the ramification
index of q times the inertia degree of q equals the rank of S as an R-module.
Let S/R be a finite flat extension of integral domains, and let p be prime ideal of R.
Assume that R is the invariant subring of a finite group G acting on S. Then the sum over
all prime ideals q of S lying over p of the ramification index of q times the inertia
degree of q equals the cardinality of G.