Etale local structure of finite maps #
We construct etale neighborhoods that split fibers of finite algebras.
Main results #
Algebra.exists_etale_isIdempotentElem_forall_liesOver_eq: LetSbe a module-finiteR-algebra, andqa prime lying overp. We may construct an etaleR-algebraR'and a primePlying overpwithκ(P) = κ(p), such thatR' ⊗[R] S = A × Band there exists a unique prime inAlying overP. This prime will also lie overq.
If q is a prime of R' lying over p, a prime of R, such that κ(q) = κ(p), then
the fiber of R' → R' ⊗[R] S over q is in bijection with the fiber of R → S over p.
Equations
- One or more equations did not get rendered due to their size.
Instances For
Suppose f : S →ₐ[R] T is an R-algebra homomorphism with S integral and T of finite type,
such that the induced map S[1/g] → T[1/g] is surjective for some g : S.
Then for any prime p of R such that 1 ⊗ₜ g is invertible in κ(p) ⊗ S,
there exists r ∉ p such that T[1/r] is finite over R[1/r].
A variant of Ideal.exists_not_mem_forall_mem_of_ne_of_liesOver that also gives you
control on the primes in the integral closure.
Let S be a finite type R-algebra, and q a prime lying over p such that S is quasi-finite
at q.
We may construct an etale R-algebra R' and a prime P lying over p with κ(P) = κ(p),
such that R' ⊗[R] S = A × B, A is finite as an R'-module,
and there exists a unique prime in A lying over P. This prime will also lie over q.
The actual lemma is stated in terms of the idempotent element e = (1, 0).
If S is finite over R, and p is a prime of R, then there exists an étale neighborhood
(R', P) of p with κ(p) = κ(P) such that R' ⊗[R] S ≃ₐ[R'] R₁ × ... × Rₙ × A,
each Rᵢ has a unique prime Pᵢ lying over P, and no other prime in R' ⊗[R] S lies over P.
This is merely an iterated application of exists_etale_isIdempotentElem_forall_liesOver_eq.
This is weaker than the corresponding statement of stacks project (in particular we asked for
Module.Finite instead of quasi finite when localized at p, so that we don't need to keep
track of this when passing to quotients and tensor products), and the only reason is that
the corresponding stronger statement is even harder to state and even more annoying to prove.