Inverse function theorem - the easy half #
THIS FILE IS SYNCHRONIZED WITH MATHLIB4. Any changes to this file require a corresponding PR to mathlib4.
In this file we prove that g' (f x) = (f' x)⁻¹
provided that f
is strictly differentiable at
x
, f' x ≠ 0
, and g
is a local left inverse of f
that is continuous at f x
. This is the
easy half of the inverse function theorem: the harder half states that g
exists.
For a more detailed overview of one-dimensional derivatives in mathlib, see the module docstring of
analysis/calculus/deriv/basic
.
Keywords #
derivative, inverse function
If f (g y) = y
for y
in some neighborhood of a
, g
is continuous at a
, and f
has an
invertible derivative f'
at g a
in the strict sense, then g
has the derivative f'⁻¹
at a
in the strict sense.
This is one of the easy parts of the inverse function theorem: it assumes that we already have an inverse function.
If f
is a local homeomorphism defined on a neighbourhood of f.symm a
, and f
has a
nonzero derivative f'
at f.symm a
in the strict sense, then f.symm
has the derivative f'⁻¹
at a
in the strict sense.
This is one of the easy parts of the inverse function theorem: it assumes that we already have an inverse function.
If f (g y) = y
for y
in some neighborhood of a
, g
is continuous at a
, and f
has an
invertible derivative f'
at g a
, then g
has the derivative f'⁻¹
at a
.
This is one of the easy parts of the inverse function theorem: it assumes that we already have an inverse function.
If f
is a local homeomorphism defined on a neighbourhood of f.symm a
, and f
has an
nonzero derivative f'
at f.symm a
, then f.symm
has the derivative f'⁻¹
at a
.
This is one of the easy parts of the inverse function theorem: it assumes that we already have an inverse function.